Question

设x^6-x^5-17x^4+5x^3+64x^2-4x-48=(x+a)(x+b)(x+c)(x+d)(x+e)(x+

Answer 1

-1

x的5次幂系数可以推出来.

(x+a)(x+b)(x+c)(x+d)(x+e)(x+f)=x^6 +(a+b+c+d+e+f)x^5+.