Question

分解因式：y（y+1）（x²+1）+x（2y²+2y+1）

Answer 1

y（y+1）（x²+1）+x（2y²+2y+1）

=y(y+1)x²+(2y²+2y+1)x+y(y+1)

=(yx+y+1)[(y+1)x+y]

=(xy+y+1)(xy+x+y)