计算[(9/m)+m-6][3/(m-3)+1]
1个回答
因为[(9/m)+m-6]=(9+m^2-6m)/m=(m-3)^2/m
[3/(m-3)+1]=(3+m-3)/(m-3)=m/(m-3)
所以[(9/m)+m-6][3/(m-3)+1]=m-3
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