x^3+y^3+xy^2+x^2y+1怎么读?

1个回答

1/x+1/y=3 ,求2x-3xy+2y/-3x+xy-3y
3x^2 y+{xy-[3x^2 y-(4xy^2 +1/2xy)]-(4x^2 y+3/2xy)}
1 （2x-3y)^2(2x+3y)^2 2 (2x+y-1)(2x+y+y) 3 (2+xy)(xy-2)-(-2+x
(3x^2y^3)/(2xy)^2=?(3x^2y^2)/(xy)*(1/y)=?x^2y-5x^2y+3x^y=?(6
(1) 1/x-1/y=3,分式(2x+3xy-2y)/(x-2xy-y)=_______
XY=1,X+Y=3,则3XY+10Y+[5X-(2XY+2Y-3X)]
求（x+3y-3xy）-2（-2x-y+xy）的值,其中x+y=1/3,xy= -1/2
求值（x^2+xy)/(x^2-2xy-3y^2)*(3y-x)/(x-y)+(x^-1+y^-1)÷(x^-1-y^-
求值（x^2+xy)/(x^2-2xy-3y^2)*(3y-x)/(x-y)+(x^-1+y^-1)÷(x^-1-y^-
【xy(x²-3y)+3xy²】(-2xy)+x³y²(2x-y)