H2O 16/18*100%=88.9%
C2H5OH 16/46*100%=34.8% X*34.8%+(1-X)*88.9%=64% 88.9%-64%=88.9%*X-34.8%*X
24.9%=54.1%*X X=0.46 水0.46酒精0.54的比例
【初三化学】将水和酒精混合,混合物中中氧元素占64%,求酒精的浓度
H2O 16/18*100%=88.9%
C2H5OH 16/46*100%=34.8% X*34.8%+(1-X)*88.9%=64% 88.9%-64%=88.9%*X-34.8%*X
24.9%=54.1%*X X=0.46 水0.46酒精0.54的比例