不用分部积分,直接拆分子.
In=∫(0→1)x^n/(1+4x)dx
=∫(0→1)(x^n+x^(n-1)/4-x^(n-1)/4)/(1+4x)dx
=1/4∫(0→1)x^(n-1)dx-1/4∫(0→1)x^(n-1)/(1+4x)dx
=x^n/(4n)|(0→1)-I(n-1)/4
=1/4(1/n-I(n-1))
不用分部积分,直接拆分子.
In=∫(0→1)x^n/(1+4x)dx
=∫(0→1)(x^n+x^(n-1)/4-x^(n-1)/4)/(1+4x)dx
=1/4∫(0→1)x^(n-1)dx-1/4∫(0→1)x^(n-1)/(1+4x)dx
=x^n/(4n)|(0→1)-I(n-1)/4
=1/4(1/n-I(n-1))