Question

初三一元二次方程 解方程解方程(1) 2(x-1)=(x-1)(x-2) (2) （x-3）²+4x(x-3)=0(3)

Answer 1

(1) 2(x-1)=(x-1)(x-2)

2(x-1)-(x-1)(x-2)=0

(x-1)(2-x+2)=0

x1=1 x2=4

(2) （x-3）²+4x(x-3)=0

(x-3)(x-3+4x)=0

x1=3 x2=3/5

(3) (2x-1)²=（3-x）²

(2x-1)²-（3-x）²=0

(2x-1+3-x)(2x-1-3+x)=0

x1=-2 x2=4/3

(4) 3x（2x+1）=4x+2

3x(2x+1)-2(2x+1)=0

(2x+1)(3x-2)=0

x1=-1/2 x2=2/3