Question

高数 求偏导数求偏z/偏xz=yln(x+√(x²+y²))+3x-2y要详细过程谢谢了x&sup2

Answer 1

z = yln[x+√(x²+y²)]+3x-2y∂z/∂x = {y/[x+√(x²+y²)]}{1 + x/√(x²+y²)} + 3= y[√(x²+y²)+x]/[x+√(x²+y²)][√(x²+y²)] + 3= y/[√(x&s...