1、∵AD⊥BC,那么∠FDC=∠BAC=∠EAC=90°
CE平分∠ACB,那么∠ACE=∠BCE=∠DCF
∴△CDF∽△CAE
2、∵∠CAD+∠BAD=90°
∠ABD+∠BAD=9°
∴∠CAD=∠ABD
即∠CAF=∠EBC
∵∠ACF=∠BCF
∴△AFC∽△BEC
1、∵AD⊥BC,那么∠FDC=∠BAC=∠EAC=90°
CE平分∠ACB,那么∠ACE=∠BCE=∠DCF
∴△CDF∽△CAE
2、∵∠CAD+∠BAD=90°
∠ABD+∠BAD=9°
∴∠CAD=∠ABD
即∠CAF=∠EBC
∵∠ACF=∠BCF
∴△AFC∽△BEC