[(1+3)(1+3^2)(1+3^4)(1+3^

[(1+3)(1+3^2)(1+3^4)(1+3^8).(1+3^32)+1/2]3*3^2*3^3*……*3^10=多

2个回答

原式=[(1-3)(1+3)(1+3^2)(1+3^4)……(1+3^32)/(1-3)+1/2]/3^55
=[(1-3^64)/(-2)+1/2]/3^55
=(-1/2+3^64/2+1/2)/3^55
=3^9/2
=9841.5

1.(3+1)*(3^2+1)*(3^4+1)*(3^8+1)*……*（3^32+1) =
计算：2(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)(3^32+1)+1
(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)(3^32+1)+1=?
3/2+3/4+3/8+1/16+1/32=
2(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)(3^32+1)的个位数是什么?
(3+1)(3^2+1)(3^3+1)(3^4+1)(3^5+1)……(3^32+1)
1.化简（1）√8+√32-√2 （2）（2+√3）（2-√3）（3）（3√3-2）² （4）√50+√1/2-√72（
(3+1)(3^2+1)(3^4+1)(3^16+1)(3^32+1)
2(3+1)(3^2+1)(3^3+1)(3^4+1)(3^8+1)+1
求和： Sn=2*1+4*(1/3)+6*(1/32)+8*(1/3^3)+…+2n(1/3^(n-1))