Question

已知关于x方程,a+1分之ax-1=x-1分之2的解与方程x分之x+1=3的解互为倒数,求a的值

Answer 1

(x+1)/x=3

x+1=3x

2x=1

x=1/2

∵ax/(a+1) -1 = 2/(x-1)的解与(x+1)/x=3的解互为倒数

∴ax/(a+1) - 1 = 2/(x-1)的解为x=2

∴2a/(a+1) - 1 = 2/(2-1) = 2

2a/(a+1) = 3

2a = 3a+3

a = -3