(1)R1R2R3R4的总电阻为6Ω(自己求一下),电压为6v,所以I=U/R=1A
总功率P=电动势xI,所以,电动势=P/I=9.6v,
(2)R0+r=(9.6-6)v/1A=3.6Ω
R3R4并联和R1串联在和R2并联,
电阻为7.5x3/10.5=2.1Ω
I=电动势/R=9.6/(3.6+2.1)=1.68A
电压表示数为U=I乘以R1R2R3R4的总电阻=1.68x2.1=3.53v
电流表的示数=U/R2+U除以R1R3R4的总电阻/2=3.53/3+(3.53/7.5)/2
=1.177+0.235=1.42A