log4(3)-log4(12)-log8(4)

log4(3)-log4(12)-log8(4) =log4(3/12)- log8( 8^(2/3) ) log8(

1个回答

这个问题是这样的
4=2²=（2^3）^(2/3)=8^(2/3)
所以 log8( 8^(2/3))=2/3
前面的是对数运算法则 loga M-loga N=loga (M/N)

(log4 3+log8 3)*(log3 2+log4 2)
(log2(3)+log8(9))x(log3(4)+log9(8)+log3(2))
若log3 4*log4 8*log8 m=log4 16求m
(log(4)3+log(8)3)(log(3)2+log(9)8) 怎么个思路
(log2 3+log8 9)(log3 4+log9 8+log3 2)的运算过程
log2(3)*log3(4)*log4(5)*log5(6)*log6(7)*log7(8)=?
计算：（log4 9+log8 3)(log3 2+log9 2)-log1/3 4√81
(iog(4)3+log(8)3)(log(3)2+log(9)8)怎样计算
求值(log3(2)+log9(2))*(log4(3)+log8(3))
NO.1 (log3 2 + log9 2) (log4 3 + log8 3)