Question

用MATLAB作出柱面x^2+y^2=4 和柱面x^2+z^2=4 相交的图形.

Answer 1

程序如下：

t=0:pi/20:2*pi;

x=sin(t)*2;

y=cos(t)*2;

z=linspace(-5,5,length(t));

X=meshgrid(x);Y=meshgrid(y);Z=[meshgrid(z)]';

mesh(X,Y,Z)%第一个圆柱面

xlabel('x')

ylabel('y')

zlabel('z')

hold on

x1=sin(t)*2;

z1=cos(t)*2;

y1=linspace(-5,5,length(t));

X1=meshgrid(x1);Y1=[meshgrid(y1)]';Z1=meshgrid(z1);

mesh(X1,Y1,Z1)%第二个圆柱面

plot3(sin(t)*2,cos(t)*2,cos(t)*2,'k-*','LineWidth',2)%交线1

hold on

plot3(-sin(t)*2,-cos(t)*2,cos(t)*2,'k-*','LineWidth',2)%交线2

title('柱面x^2+y^2=4 和柱面x^2+z^2=4 相交的图形')

结果：