Question

(x^2-3x-2)(x^2-3x+4)-16因式分解,

Answer 1

(x²-3x-2)(x²-3x+4)-16

=[(x²-3x)-2][(x²-3x)+4]-16

=(x²-3x)²+2(x²-3x)-8-16

=(x²-3x)²+2(x²-3x)-24

=[(x²-3x)+6][(x²-3x)-4]

=(x²-3x+4)(x²-3x-4)

=(x²-3x+4)(x+1)(x-4)