a=√3>1
a-1>0
|a-1|=a-1
原式=[(a-1)²/(a-1)]-√(a-1)²/a(a-1)
=(a-1)-|a-1|/a(a-1)
=a-1-(a-1)/a(a-1)
=a-1-1/a
=√3-1-1/√3
=2√3/3-1