先对外函数y = cos(u)求导,再乘以内函数u = arcsinx / 2的导数
y = cos(arcsinx / 2)
y' = -sin(arcsinx / 2) × 1/2*1/√(1-x²)
= [-sin(arcsinx / 2)]/[2√(1-x²)]
先对外函数y = cos(u)求导,再乘以内函数u = arcsinx / 2的导数
y = cos(arcsinx / 2)
y' = -sin(arcsinx / 2) × 1/2*1/√(1-x²)
= [-sin(arcsinx / 2)]/[2√(1-x²)]