Question

y=sinxcosx+8的周期是?

Answer 1

y=f(x)=sinxcosx+8

=1/2·2sinxcosx+8

=1/2·sin2x+8

所以,f(x+π)=1/2·sin(2x+π)+8=1/2·sin2x+8=f(x)

即 该函数的周期为π.