设作对n道的人数为xn
x1 = 7
x2 = x3
x5 = 6
x1+x2+x3+x4+x5 = 52
x1 + 2*x2 + 3*x3 + 4*x4 + 5*x5 = 52*5 - 4 - 6 - 10- 20 - 39
解此方程组
7+2*x2 + x4 + 6 = 52 -> x4 = 39 - 2*x2
7 + 5 * x2 + 4* x4 + 30 = 181
得
x2 = 4,x4 = 31
设作对n道的人数为xn
x1 = 7
x2 = x3
x5 = 6
x1+x2+x3+x4+x5 = 52
x1 + 2*x2 + 3*x3 + 4*x4 + 5*x5 = 52*5 - 4 - 6 - 10- 20 - 39
解此方程组
7+2*x2 + x4 + 6 = 52 -> x4 = 39 - 2*x2
7 + 5 * x2 + 4* x4 + 30 = 181
得
x2 = 4,x4 = 31