答案是x+49
2x+3(2x-1)16一(x+1)
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相关问题
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解方程 3(X-1)+16(2X-3)=-16 (2X+1)÷3-(X-1)÷6=2
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(-2x-1)2(2x-1)2-16(x+3)2(x-3)2.
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解方程(1)[x−1/4−1=2x+16](2)3(x+1)-2(x+2)=2x+3.
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解一元二次方程(x+1)²=5(2x+1)²=5(-x-1)²=4x²-2x+1=3x²-8x+16=7(3x-2)²=
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(x+4)(x^2+16)(x-4),(x-1/3)(x^2+1/9)(x+1/3),
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(2X-1)²=16(3X+2)²
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16(3x-2)²=(1-2x)²
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[2x−1/3−10x−16=2x+14−1
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(x-1/2)(2x+1)(2x^2+1/2)(4x^4+1/4)(16x^6+1/16)/(256x^16-1/256
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因式分解的几道题,如下①-x^4+16 ②3x^2-1/3 ③-(x+2)^2+16(x-1)^2 ④(3x-2y)^2