Question

一道数学几何证明题（关于角平分线的）

Answer 1

OA=OC OB=OD ∠BOC=∠DOA ==>⊿OBC≌⊿ODA ==>∠OAD=∠OCB 和∠OBC=∠ODA

∠OAD=∠OCB 和∠OBC=∠ODA和对角相等 ==>⊿ABP≌⊿CDP==>AP=CP

AP=CP ∠OAD=∠OCB OA=OC ==>⊿OAP≌⊿OCP ==>∠AOP=∠COP ==>角平分线