Question

(a的平方+8a+16分之16-a)+(2a+8分之a-4)*(a+2分之a-2)

Answer 1

(a²+8a+(16-a)/16)+(2a+(a-4)/8)(a+(a-2)/2)

=(16a²+8×16a+16-a)/16+(16a+a-4)(2a+a-2)/16

=[(16a²+127a+16+(17a-4)(3a-2)]/16

=(16a²+127a+16+51a²-12a-34a+8)/16

=(67a²+81a+24)/16