你好
(x³+3x²y-5xy²+6y³+1)-(2x³-y³-2xy²-x²y-2)-(4x²y+7y³-x³-3xy²-1)
=x³+3x²y-5xy²+6y³+1-2x³+y³+2xy²+x²y+2-4x²y-7y³+x³+3xy²+1
=(x³-2x³+x³)+(3x²y+x²y-4x²y)+(-5xy²+2xy²+3xy²)+(6y³+y³-7y³)+(1+2+1)
=0+0+0+0+4
=4
代数式(x³+3x²-5xy²+6y³+1)-(2x³-y³-2xy²-x²y-2)-(4x²y+7y³-x³-3xy²-1)的值是一个常数
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