Question

已知三角形ABC的周长为根号2+1,且sinA+sinB=根号2乘以sinC

Answer 1

sinA + sinB = √2sinCa/sinA = b/sinB = c/sinC有：(a+b+c)/(sinA+sinB+sinC) =(a+b)/(sinA+sinB)=c/sinC所以有：(√2 + 1 - c)/(√2sinC) = c/sinC那么：√2 + 1 - c = √2c所以,AB = c = 1S = 1/2 * a * b * sinC...