假设丙烷CxHy
方程式:
CxHy +(x+y/4)O2 =xCO2 + (y/2)H2O
44 32(x+y/4) 44x 18y/2
11g 40g 33g 18g
44:44x=11:33
x=3
44:9y=11:18
y=8
所以丙烷分子式C3H8
假设丙烷CxHy
方程式:
CxHy +(x+y/4)O2 =xCO2 + (y/2)H2O
44 32(x+y/4) 44x 18y/2
11g 40g 33g 18g
44:44x=11:33
x=3
44:9y=11:18
y=8
所以丙烷分子式C3H8