Question

求函数y=根号3sin(2π/5乘以x-π/3）的单调区间

Answer 1

增：

2kπ-π/2≤(2π/5)x-π/3≤2kπ+π/2

2kπ-π/6≤(2π/5)x≤2kπ+5π/6

5kπ-5π/12≤x≤5kπ+25π/12

增区间 【5kπ-5π/12,5kπ+25π/12】,k∈Z

减

2kπ+π/2≤(2π/5)x-π/3≤2kπ+3π/2

2kπ+5π/6≤(2π/5)x≤2kπ+11π/6

5kπ+25π/12≤x≤5kπ+55π/12

减区间 【5kπ+25π/12,5kπ+55π/12】,k∈Z