Question

y=cos[（15/2）p-(2/3)x]的奇偶性

Answer 1

p应该是圆周率的pi吧,奇函数,化简 f(x)=cos(15/2*pi-2/3*x),

f(-x)=cos(3/2*pi-2/3*x)=cos(3/2*pi+2/3*x)=cos(-3/2*pi-2/3*x)= -cos(-3/2*pi-2/3*x+3*pi)= -cos(3/2*pi-2/3*x)=-f(x),所以奇函数