Question

设M=8/根号2008-44,a是M的整数部分,b是M的小数部分,求a²+3（根号2008+37）ab+10

Answer 1

M=8/sqr2008-44=9.87

a=9,b=M-a=(8/sqr2008-44)-9=(sqr2008+44)/9-9

a^2+3(sqr2008+37)ab+10

=9*9+3(sqr2008+37)*9*[(sqr2008+44)/9-9]+10

=81+3(sqr2008+37)*(sqr2008+44-81)+10

=81+3(2008-37^2)+10

=81+1917+10

=2008