f(x)=sin(x+3π/4)+cos(x+3π/4)
=√2[√2/2*sin(x+3π/4)+ √2/2*cos(x+3π/4)]
=√2 sin[(x+3π/4)+ π/4]
=√2 sin(x+π)
=-√2 sinx
所以函数的最小正周期是2π,是奇函数.
f(x)=sin(x+3π/4)+cos(x+3π/4)
=√2[√2/2*sin(x+3π/4)+ √2/2*cos(x+3π/4)]
=√2 sin[(x+3π/4)+ π/4]
=√2 sin(x+π)
=-√2 sinx
所以函数的最小正周期是2π,是奇函数.