3/2*5/4*7/6*9/8*...2k+1/2k*2k+3/2k+2>√k+1*2k+3/2k+2
再证左式>√k+2即可
√k+1*2k+3/2k+2>√k+1*2k+3/2k+2
两边平方后,合并同类项
即K+1>0
命题得证