√2 x²-4x=4
√2 x²-4x-4=0
b²-4ac=﹙﹣4﹚²-4×√2×﹙﹣4﹚=16+16√2
x=[﹣b±√﹙b²-4ac﹚]/2a
=[4±4√﹙√2+1﹚]/2√2
=√2±√﹙2+√2﹚
x1=√2+√﹙2+√2﹚
x2=√2-√﹙2+√2﹚.
√2 x²-4x=4
√2 x²-4x-4=0
b²-4ac=﹙﹣4﹚²-4×√2×﹙﹣4﹚=16+16√2
x=[﹣b±√﹙b²-4ac﹚]/2a
=[4±4√﹙√2+1﹚]/2√2
=√2±√﹙2+√2﹚
x1=√2+√﹙2+√2﹚
x2=√2-√﹙2+√2﹚.