Question

抛物线的方程为y=ax^2,试求抛物线的焦点坐标

Answer 1

x² = 2py,焦点为(0,p/2),准线为y = -p/2

y = ax²,x² = y/a,此时p = 1/(2a),焦点为(0,1/(4a)),准线为y = -1/(4a)