5y+1/6=9y+1/8-1-y/3

3个回答

  • (5y+1)÷6=(9y+1)÷8-(1-y)÷3

    [(5y+1)÷6]×24=[(9y+1)÷8-(1-y)÷3]×24

    4×(5y+1)=3×(9y+1)-8×(1-y)

    20y+4=27y+3-8+8y

    20y-27y-8y=3-8-4

    -15y=-9

    y=3/5

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