1个两位数是它数字之和的7倍.如果数字颠倒,新的两位数是它和的N倍,求N
答案是4
可以设这个数为10X+y
易得10X+Y=7(X+Y)
求10Y+X=N(X+Y)
上下两式一加得N=4
a two digit number is seven times the sum of its digits.if t
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