(x²-x)²+(x²-x)-6=0
设x²-x=a
则有:
a²+a-6=0
(a-2)(a+3)=0
a=2或a=-3
当a=2时
x²-x=2
x²-x-2=0
(x+1)(x-2)=0
x=-1或x=2
当a=-3时
x²-x=-3
x²-x+3=0
△=1-12=-11
(x²-x)²+(x²-x)-6=0
设x²-x=a
则有:
a²+a-6=0
(a-2)(a+3)=0
a=2或a=-3
当a=2时
x²-x=2
x²-x-2=0
(x+1)(x-2)=0
x=-1或x=2
当a=-3时
x²-x=-3
x²-x+3=0
△=1-12=-11