求y=2x*tanx导数

1个回答

  • (tanx)'

    = (sinx/cox)'

    = (sinx)' * (1/cosx) + sinx * (1/cosx)'

    = cosx/cosx + sinx * [-(cosx)'/(cosx)^2]

    = 1 + sinx*sinx/(cosx)^2

    = 1 + (sinx)^2/(cosx)^2

    = [(cosx)^2 + (sinx)^2]/(cosx)^2

    = 1/(cosx)^2

    y=2xtanx

    y' = (2x)' * tanx + 2x * (tanx)'

    = 2 tanx + 2x /(cosx)^2

    = (2sinx*cosx + 2x)/(cosx)^2

    = (sin2x + 2x)/(cosx)^2