Question

质量为2千克的物体,从长6.6米的斜面顶端由静止下滑,斜面倾角为30度,物体与斜面间的动摩擦因数为0.2

Answer 1

p=mgvcos(60)=mg1/2(0+vt)cos(60)

vt^2=2[gsin(30)-0.2gcos(30)]6.6

p=?

(2)

p=mgvtcos(60)