Question

初三用因式分解法求解一元二次方程

Answer 1

2、［3(X-2)+2(X+1)］［3(X-2)-2(X+1)］=0,

(5X-4)(X-8)=0,

X1=4/5,X2=8.

3、3(X+1)(X-1)-(X-1)^2=0

(X-1)［3(X+1)-(X-1)］=0

(X-1)(2X+4)=0

X1=1,X2=-2.