f(x)= (√3/2)*sin2(ωx+α)-[1+cos2(ωx+α)]/2
=sin2(ωx+α)cosπ/6-cos2(ωx+α)sinπ/6-1/2
=sin[2(ωx+α-π/6)-1/2.
=sin(2ωx+2α-π/3). (0
已知函数f（x）=根号3•sin（wx+a）•cos（wx+a）-cos^2（wx+a）,0＜a
1个回答
相关问题
-
设函数f(x)=cos(wx)^2+根号3sin(wx)cos(wx)=a
-
已知函数f(x)=根号3sin(wx+φ)-cos(wx+φ)(0
-
[非常急]已知函数f(x)=根号3sin(wx+φ)-cos(wx+φ)(0
-
已知函数f(x)=√3sin(wx+φ)-cos(wx+φ)(0
-
求已知函数f(x)=根号3sin(wx＋坏塔）-cos(wx+坏塔）（0
-
已知函数f(x)+sin(wx+pi/6)+根号3cos(wx+pi/6)(w>0)
-
已知函数f(x)=sin(wx+π/6)+sin(wx-π/6)-2cos^2 wx/2 w＞0 若对任意a属于R,函数
-
已知函数f x=√3sin(wx+φ/2)*cos(wx+φ/2)+sin^2(wx+φ/2)(w>0,0
-
已知函数f(x)=sin(wx+π/6)+sin(wx-π/6)-2cos^2 wx/2 w＞0
-
已知函数f(x)=cos²wx+2根号3coswx×sinwx-sin²wx(w>0),且f(x)相