Question

随机变量概率密度问题随机变量X的概率密度函数为-1

Answer 1

y≤1时,Fy(y)=0；

2≥y>1时,

Fy(y)

=∫[-根号(y-1),根号(y-1)]f(x)dx

=2∫[0,根号(y-1)](1-x)dx

=2(x-x^2/2)|[0,根号(y-1)]

=2根号(y-1)-y+1

y>2时,

Fy(y)=1;

所以y