n(Zn)=13/65=0.2mol
n(HCl)=0.48*2=0.96mol
Zn+2HCL=H2(气体)+ZnCL2
1 2 1 1
0.2 x y z
x=0.4mol y=0.2mol z=0.2mol
V(H2)=0.2*22.4=4.48L
n(HCl)剩余=0.96-0.4=0.56mol
C(HCl)=0.56/0.5=1.12mol/L
C(ZnCL2)=0.2/0.5=0.4mol/L
n(Zn)=13/65=0.2mol
n(HCl)=0.48*2=0.96mol
Zn+2HCL=H2(气体)+ZnCL2
1 2 1 1
0.2 x y z
x=0.4mol y=0.2mol z=0.2mol
V(H2)=0.2*22.4=4.48L
n(HCl)剩余=0.96-0.4=0.56mol
C(HCl)=0.56/0.5=1.12mol/L
C(ZnCL2)=0.2/0.5=0.4mol/L