Question

设A为5阶反对称矩阵,证明杠杠A杠杠＝0

Answer 1

由A为反对称矩阵

所以 A' = -A

所以 |A| = |A'| = |-A| = (-1)^5 |A| = -|A|

所以 2|A| = 0

所以 |A| = 0

A'是A的转置

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