Question

A,B,C,D,E,F是1到9之间得到任何数,ABCDEF*2=CDEFAB,CDEFAB*2=EFABCD,ABCDE

Answer 1

a = 1,b = 4,c = 2,d = 8,e = 5,f = 7

C代码:

# include

//根据题意确定循环上下限

int max = 1000000;

int min = 1000000 / 2 / 2;

int ABCDEF;

int CDEFAB;

int EFABCD;

int main(int argc,char **argv)

{

for (ABCDEF = 100000; ABCDEF < min; ABCDEF++)

{

int A = ABCDEF / 100000;

int B = (ABCDEF % 100000) / 10000;

int C = (ABCDEF % 10000) / 1000;

int D = (ABCDEF % 1000) / 100;

int E = (ABCDEF % 100) / 10;

int F = (ABCDEF % 10);

if (C