∫sin^5x/cos^4xdx,

1个回答

  • ∫[(sinx)^5/(cosx)^4]dx

    =-∫[(sinx)^4/(cosx)^4]d(cosx)

    =-∫{[1-(cosx)^2]^2/(cosx)^4}d(cosx)

    =-∫{[1-2(cosx)^2+(cosx)^4]/(cosx)^4}d(cosx)

    =-∫[1/(cosx)^4]d(cosx)-2∫[1/(cosx)^2]d(cosx)-∫d(cosx)

    =(1/3)/(cosx)^3-2tanx-cosx+C.