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看算式,找规律.7x1=7 7x7=49 7x7x7=343 7x7x7x7=2401 7x7x7x7x7=16807
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相关问题
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观察下列算式：7 1 =7，7 2 =49，7 3 =343，7 4 =2401，7 5 =16807，7 6 =117
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(-8)x(-80/7)+(-7)x(-80/7)+(-15)x80/7
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(x+2)^3-(x+2)-(7^3-1) =(x+2-7)[(x+2)^2+7(x+2)+49]-(x+2-7)中^是
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7(6x+1)-6(7-x)=7
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求[(x-y)+7][(x-y)^2-7(x-y)+49]-343的立方根
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(5-7X)/8=(7-5X)/7-1
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(-7x-3y)(-7x-3y)(-7x+3y)(-7x+3y)=?
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1/(x^2+7x)-1/(x^2+7x+6)+1/(x^2+7x+18)-1/(x^2+7x+12)=0
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已知集合中={x|x7-中x+中7-19=0}，你={x|x7-1x+6=0}，C={x|x7+7x-8=0}
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7(X+1)=7X+7判断题对吗