6道数学因式分解(1)2x(x-y)四次方-x²(x-y)²+xy(y-x)²(2)8a三

3个回答

  • (1)

    2x(x-y)^4-x²(x-y)²+xy(y-x)²

    =x(x-y)²[2(x-y)²-x+y]

    =x(x-y)²[2(x-y)²-(x-y)]

    =x(x-y)²(x-y)[2(x-y)-1]

    =x(x-y)³(2x-2y-1)

    (2)

    8a³-b³

    =(2a)³-b³

    =(2a-b)(4a²+2ab+b²)

    (3)

    (x-y+1)+y(y-2x)

    =4x-4y+4+y²-2xy

    =(y-2)²-2x(y-2)

    =(y-2)(y-2-2x)

    (4)

    3x²+5xy-2y²+x+9y-4【题有误,最后一项应该是-4而不是+4,若被猜对请往下看】

    3x²+x(5y+1)-(2y²-9y+4)

    =3x²+x(5y+1)-(2y-1)(y-4)

    =[3x-(y-4)][x+(2y-1)]

    =(3x-y+4)(x+2y-1)

    (5)

    2x²+xy-y²-4x+5y-6

    =2x²+(y-4)x+(-y2+5y-6)

    =2x²+(y-4)x+[-(y2-5y+6)]

    =2x²+(y-4)x+[-(y-2)(y-3)]

    =[1x+(y-3)][2x+(-y+2)]

    =(x+y-3)(2x-y+2)

    (6)

    3x²-4xy+y²【题目有误,应该是+y²,-y²的话无法分解,若猜对的话请往下看】

    =(3x-y)(x-y)