Question

已知f(x-3)=logx/(6-x) (a＞0,且a≠1),试判断f(x）的奇偶性

Answer 1

x-3=t,x=t+3

f(t)=log(t+3)/(3-t)

f(-t)=log(3-t)/(3+t)=-log(t+3)/(3-t)=-f(t)

为奇函数.