设甲乙两筐原有苹果5X千克和9X千克
(5X-20+30):(9X+20-30)=3:4
(5X+10):(9X-10)=3:4
3(9X-10)=4(5X+10)
27X-30=20X+40
7X=70
X=10
5X=50
9X=90
答:甲乙俩筐原有苹果分别有50千克和90千克.
设甲乙两筐原有苹果5X千克和9X千克
(5X-20+30):(9X+20-30)=3:4
(5X+10):(9X-10)=3:4
3(9X-10)=4(5X+10)
27X-30=20X+40
7X=70
X=10
5X=50
9X=90
答:甲乙俩筐原有苹果分别有50千克和90千克.