Question

已知m²n²-8mn+4m²+n²+4=0,求3m+（二分之n）的二零一四次方的

Answer 1

m^2n^2-8mn+4m^2+n^2+4=0

m^2n^2-4mn+4+4m^2-4mn+n^2=0

(mn-2)^2+(2m-n)^2=0

mn=2

2m-n=0 2m=n

m(2m)=2

m^2=1

m1=1,n1=2.3m+(n/2)^2013=3+1=4

m2=-1,n2=-2.3m+(n/2)^2013=-3-1=-4