Question

程序设计 求能被6整除且只有一位数字为8的三位数之和

Answer 1

int i = 3;

int sum = 0;

int s;

do

{

s = i * 6;

int k = 0;

k += (s / 100) == 8 1 :0;

k += ((s / 10) % 10 == 8) 1 :0;

k += (s % 10 == 8) 1 :0;

if (k == 1) sum += s;

i++;

} while (s < 999);

printf("result:%dn",sum);